Mechanical Properties of SolidsNEET MCQs with solutions
Mechanical Properties of Solids covers stress, strain, Young's modulus, bulk modulus, shear modulus, Poisson's ratio and the stress-strain curve. NEET tests elastic moduli calculations, stress-strain graph interpretation and Hooke's law application. Questions are mostly numerical and formula-based.
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- 11 Physics
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- 24 questions
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- 382 questions
- ELITE questions
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- NCERT topics
- 8
Practise 24 questions
Tap an option to check it. Questions from every NCERT topic in this chapter, from easy to hard.
Q1Elastic Behaviour of Solids
Which property enables a material to regain its original shape and size after the deforming force is removed, provided the elastic limit is not exceeded?
Not quite — the answer is A.
Elasticity is the property by which a body regains its original configuration after removal of deforming force. Plasticity causes permanent deformation, so Option B is wrong.
Q2Elastic Behaviour of Solids
According to NCERT, the deformation produced in a body depends primarily on:
Not quite — the answer is B.
Deformation depends on both the applied force and the elastic properties of the material. Options A, C, D are each incomplete and exclude essential contributing factors.
Q3Elastic Behaviour of Solids
Which statement correctly distinguishes elastic and plastic behaviour?
Not quite — the answer is C.
Elastic deformation disappears fully after force removal; plastic deformation persists. Option B is the opposite of the correct definition of plasticity.
Q4Stress and Strain
Longitudinal strain is defined as:
Not quite — the answer is C.
Longitudinal strain = ΔL/L₀ — ratio of change in length to original length, always dimensionless. Option D is the reciprocal, the most common error. Option A defines area strain; Option B defines volumetric strain.
Q5Stress and Strain
A wire of original length 2 m elongates by 2 mm under a load. The longitudinal strain produced is:
Not quite — the answer is A.
Strain = ΔL/L = (2 × 10⁻³) / 2 = 1 × 10⁻³. Option C (2 × 10⁻³) traps students who correctly convert mm to m but forget to divide by L. Option B (10⁻²) arises from a decimal-place error in unit conversion.
Q6Stress and Strain
When a wire is stretched, its length increases while its lateral dimensions decrease. Which of the following correctly explains the sign relationship between longitudinal and lateral strain?
Not quite — the answer is A.
Stretching gives positive longitudinal strain and negative lateral strain — always opposite in sign. Option D is the NEET-style trap: magnitudes are equal only for a specific Poisson's ratio of 0.5; in general they differ. Option B wrongly equates signs.
Q7Hooke's Law and Elastic Moduli
A wire of length 2 m extends by 1 mm under a tensile stress of 1 × 10⁸ Pa. The Young's modulus of the material is:
Not quite — the answer is A.
Strain = ΔL/L = 10⁻³/2 = 5 × 10⁻⁴. Y = stress/strain = 10⁸/5 × 10⁻⁴ = 2 × 10¹¹ Pa. Option B arises from using ΔL directly as strain without dividing by L. Option D confuses Young's modulus with the applied stress value.
Q8Hooke's Law and Elastic Moduli
Which material is most suitable for manufacturing machine tools that must undergo minimum deformation under load?
Not quite — the answer is B.
Minimum deformation requires maximum stiffness — the largest Young's modulus. Steel has Y ≈ 2 × 10¹¹ Pa, far greater than rubber (~10⁶ Pa), wood (~10¹⁰ Pa), or plastic (~10⁹ Pa).
Q9Hooke's Law and Elastic Moduli
For the same applied stress, a material with a higher Young's modulus experiences less strain. Which of the following correctly explains this?
Not quite — the answer is A.
From Y = stress/strain, rearranging gives strain = stress/Y. For fixed stress, strain is inversely proportional to Y. Option D is the classic direct-proportionality inversion error students make.
Q10Grand Test
A wire of length 2 m extends by 2 mm under a tensile stress of 2×10⁸ Pa. The Young's modulus of the material is:
Not quite — the answer is C.
Strain = ΔL/L = (2×10⁻³)/2 = 10⁻³. Y = Stress/Strain = (2×10⁸)/(10⁻³) = 2×10¹¹ Pa. Option D is the trap — copying stress directly without dividing by strain.
Q11Grand Test
A material is stressed beyond its proportional limit but has not yet reached its elastic limit. Which of the following correctly describes this region?
Not quite — the answer is A.
The proportional limit marks the end of Hooke's law. Between the proportional limit and elastic limit, stress is no longer proportional to strain, but full recovery still occurs. Permanent deformation only begins beyond the elastic limit.
Q12Grand Test
A wire has Young's modulus 2×10¹¹ Pa. If the strain produced is 5×10⁻⁴, the stress developed is:
Not quite — the answer is A.
Stress = Y × Strain = (2×10¹¹)(5×10⁻⁴) = 1×10⁸ Pa. Option B arises from a powers-of-ten error giving 10⁷. Option C arises from using strain as 10⁻³ instead of 5×10⁻⁴. Option D arises from multiplying Y × Y × strain.
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Get RankUp on Google PlayQ13Mixed Revision
A steel wire and a copper wire have identical length and cross-sectional area. They are subjected to the same tensile force. Which quantity is the same for both wires?
Not quite — the answer is B.
Stress = F/A. Since force and area are identical, stress is the same for both wires. Strain = stress/Y and extension = FL/AY both differ because Y differs between steel and copper.
Q14Mixed Revision
A wire has Young's modulus 2 × 10¹¹ Pa. If the stress applied is 4 × 10⁸ Pa, the strain produced is:
Not quite — the answer is C.
Strain = Stress/Y = (4×10⁸)/(2×10¹¹) = 2×10⁻³. Trap A: student uses stress coefficient 4 but skips dividing by Y coefficient 2. Trap D: student multiplies coefficients (4×2=8) instead of dividing.
Q15Mixed Revision
Which of the following correctly states why Young's modulus — and not the amount of extension — is the proper measure of elasticity?
Not quite — the answer is A.
Y = stress/strain: for the same stress, smaller strain means larger Y and greater elasticity. Steel extends less than rubber under equal stress, making steel more elastic. Option B reverses the relationship.
Q16Stress–Strain Curve
The initial straight-line portion of the stress–strain curve represents:
Not quite — the answer is A.
In the linear region, stress ∝ strain and the slope equals Young's modulus. All other regions — plastic, necking, fracture — occur at higher stresses well beyond the elastic region.
Q17Stress–Strain Curve
The point on the stress–strain curve beyond which stress is no longer proportional to strain is called the:
Not quite — the answer is B.
The proportional limit is the specific point up to which stress ∝ strain and the graph is linear. Beyond it the curve becomes non-linear even if the material is still elastic. The elastic limit lies at or beyond the proportional limit.
Q18Stress–Strain Curve
All of the following correctly describe the linear (OA) region of the stress–strain curve EXCEPT:
Not quite — the answer is C.
Permanent deformation begins only after the elastic limit is exceeded — which lies beyond the linear region OA. In OA, deformation is completely reversible and Hooke's law holds throughout.
Q19NCERT Hidden Facts, PYQs and Integrated Concepts
According to NCERT, which of the following statements is correct regarding elasticity?
Not quite — the answer is A.
Young's modulus measures degree of elasticity. Steel has a far larger Young's modulus than rubber and is therefore more elastic in the scientific sense, despite rubber showing larger deformation.
Q20NCERT Hidden Facts, PYQs and Integrated Concepts
Which quantity is represented by the slope of the initial straight-line portion of the stress-strain graph?
Not quite — the answer is B.
In the Hooke's law region, Stress = Y × Strain. The slope of the linear portion is Stress/Strain = Young's modulus. Bulk modulus relates to volumetric stress, not this graph's slope.
Q21NCERT Hidden Facts, PYQs and Integrated Concepts
A material is stressed beyond its proportional limit but is still within its elastic limit. Which of the following correctly describes this situation?
Not quite — the answer is A.
Elastic limit is the maximum stress for complete recovery. Between proportional limit and elastic limit, Hooke's law fails but recovery is still complete. Permanent deformation only begins beyond the elastic limit.
Q22Applications of Elastic Behaviour
Why is steel generally preferred over aluminium for constructing bridges and building frameworks?
Not quite — the answer is B.
Higher Young's modulus means greater stiffness. Steel deforms less than aluminium under identical load, making it safer for structural use. Density and melting point are not the basis for this choice.
Q23Applications of Elastic Behaviour
A crane cable is designed with a large cross-sectional area primarily to:
Not quite — the answer is A.
Stress = F/A. Larger area reduces stress and also reduces extension since ΔL = FL/AY. Density and thermal conductivity are unrelated to the structural purpose of cable thickness.
Q24Applications of Elastic Behaviour
A suspension bridge cable should operate well below its elastic limit because:
Not quite — the answer is C.
Cables experience repeated loading cycles. Operating below the elastic limit ensures complete recovery after unloading and prevents permanent structural deformation.
ELITE question · AIR under 50 level
This chapter has 137 ELITE questions for students aiming at the very top. They are only in the app.
Unlock ELITE questions in the appKey Elasticity Concepts
Quick revision: most questions in this chapter test these facts.
| Concept | Key Fact |
|---|---|
| Stress | Force per unit area (F/A); units: Pa or N/m² |
| Strain | Fractional change: ΔL/L (longitudinal), ΔV/V (volumetric), tanθ (shear) |
| Young's modulus (Y) | Y = stress/strain = (F/A)/(ΔL/L); for longitudinal deformation |
| Bulk modulus (B) | B = −V(ΔP/ΔV); resistance to uniform compression |
| Hooke's law | Stress ∝ strain (within elastic limit); F = kx for springs |
| Stress-strain curve | Proportional limit → elastic limit → yield point → ultimate strength → fracture |
What the app covers in this chapter
382 questions in total, each with a detailed explanation.
| Elastic Behaviour of Solids | 60 |
| Stress and Strain | 59 |
| Hooke's Law and Elastic Moduli | 58 |
| Grand Test | 56 |
| Mixed Revision | 54 |
| Stress–Strain Curve | 39 |
| NCERT Hidden Facts, PYQs and Integrated Concepts | 36 |
| Applications of Elastic Behaviour | 20 |
Questions students ask
Is Mechanical Properties of Solids important for NEET?
Moderately — 1 question usually appears. Young's modulus calculations and stress-strain curve interpretation are the most tested topics.
Which topics should I revise first?
Master the three elastic moduli (Young's, Bulk, Shear) with formulas, stress-strain curve key points, and Hooke's law application in numerical problems.
How many questions from this chapter are on RankUp?
The RankUp app has 382 questions on Mechanical Properties of Solids, including 137 ELITE questions. Every question has a detailed explanation.
