Mechanical Properties of Solids NEET PYQReal NEET & AIPMT 2013–2020 questions, year-tagged, with solutions
By the RankUp team, founded by Dr. Deepak Sahu (MBBS Gold Medalist, NEET PG AIR 1731) · Updated
Every Mechanical Properties of Solids question from the NEET & AIPMT papers on this site (2013–2020), newest first. Each is tagged with its paper. Tap an option to check your answer and read the explanation.
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Mechanical Properties of Solids previous year questions
7 questions. Tap an option to check your answer.
Q1NEET 2020 · Q161
A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L₁ when mass M is suspended from its free end. The expression for Young’s modulus is :
Not quite — the answer is D.
Y = stress/strain = (Mg/A)/((L₁ − L)/L) = MgL/(A(L₁ − L)). The strain uses the extension L₁ − L, not the new length L₁, and the extension goes in the denominator.
Q2NEET 2019 · Q1
When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is:
Not quite — the answer is C.
Elastic energy stored = ½ × force × extension = ½ × Mg × l. Using MgL confuses the original length with the extension, and Mgl forgets the factor ½ (the average force during stretching is half the final force).
Q3NEET 2018 · Q44
Two wires are made of the same material and have the same volume. The first wire has cross-sectional area A and the second wire has cross-sectional area 3A. If the length of the first wire is increased by Δl on applying a force F, how much force is needed to stretch the second wire by the same amount?
Not quite — the answer is C.
F = YAΔl/L. Equal volume means the second wire has length L/3. F′ = Y(3A)Δl/(L/3) = 9 × YAΔl/L = 9F. Considering only the area change would give 3F.
Q4NEET 2017 · Q161
The bulk modulus of a spherical object is 'B'. If it is subjected to uniform pressure 'p', the fractional decrease in radius is:
Not quite — the answer is D.
Volumetric strain ΔV/V = p/B, and for a sphere V ∝ r³ so ΔV/V = 3Δr/r. Hence Δr/r = p/3B. p/B is the fractional change in volume, not radius.
Q5AIPMT 2015
The approximate depth of an ocean is 2700 m. The compressibility of water is 45.4 × 10⁻¹¹ Pa⁻¹ and density of water is 10³ kg/m³. What fractional compression of water will be obtained at the bottom of the ocean?
Not quite — the answer is D.
Pressure at the bottom ≈ hρg = 2700 × 10³ × 10 = 2.7 × 10⁷ Pa. Fractional compression ΔV/V = compressibility × pressure = 45.4 × 10⁻¹¹ × 2.7 × 10⁷ ≈ 1.2 × 10⁻² (1.20 × 10⁻² with g = 9.8).
Q6AIPMT 2014
Copper of fixed volume 'V' is drawn into wire of length 'l'. When this wire is subjected to a constant force 'F', the extension produced in the wire is 'Δl'. Which of the following graphs is a straight line?
Not quite — the answer is A.
Δl = Fl/(AY), and with fixed volume A = V/l, so Δl = Fl²/(VY). Hence Δl is proportional to l², giving a straight line against l², not against l.
Q7NEET 2013
The following four wires are made of the same material. Which of these will have the largest extension when the same tension is applied ?
Not quite — the answer is A.
Extension ΔL = FL/(AY) ∝ L/d² for the same material and tension. L/d² = 50/0.25 = 200, 100/1 = 100, 200/4 = 50 and 300/9 ≈ 33 (cm/mm²), so the 50 cm, 0.5 mm wire stretches most. The longest wire is not the answer because its larger area wins.
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